Cayley-Hamilton Theorem

Every linear operator satisfies its own characteristic polynomial
Cayley-Hamilton Theorem

Cayley-Hamilton Theorem: Let TT be a on a finite-dimensional vector space VV over a field FF, and let χT(t)\chi_T(t) be its . Then

χT(T)=0, \chi_T(T)=0,

meaning that when χT(t)\chi_T(t) is expanded as a polynomial χT(t)=tn+cn1tn1++c0\chi_T(t)=t^n+c_{n-1}t^{n-1}+\cdots+c_0, one has

Tn+cn1Tn1++c0I=0 T^n+c_{n-1}T^{n-1}+\cdots+c_0 I=0

as operators on VV (where II is the identity operator and 00 is the zero operator).

A key consequence is that the of TT divides χT\chi_T.

Proof sketch: Choose a basis so that TT is represented by a matrix AA. Over the polynomial ring F[t]F[t] one has the adjugate identity (tIA)adj(tIA)=det(tIA)I(tI-A)\operatorname{adj}(tI-A)=\det(tI-A)\,I. Interpreting both sides as matrix polynomials and substituting t=At=A (which makes sense because AA commutes with its powers) yields χA(A)=0\chi_A(A)=0, hence χT(T)=0\chi_T(T)=0.