Continuous function attains max and min on a compact set

Corollary (Extreme Value Theorem): Let (X,d)(X,d)(X,d) be a compact metric space and let f:X→Rf:X\to\mathbb{R}f:X→R be continuous . Then there exist xmin⁡,xmax⁡∈Xx_{\min},x_{\max}\in Xxmin​,xmax​∈X such that f(xmin⁡)=HAHAHUGOSHORTCODE585s3HBHBx∈Xf(x),f(xmax⁡)=HAHAHUGOSHORTCODE585s4HBHBx∈Xf(x). f(x_{\min})=min _{x\in X} f(x),\qquad f(x_{\max})=max _{x\in X} f(x). f(xmin​)=HAHAHUGOSHORTCODE585s3HBHBx∈X​f(x),f(xmax​)=HAHAHUGOSHORTCODE585s4HBHBx∈X​f(x). ...

1 min

Continuous function on a compact set is bounded

Corollary: Let (X,d)(X,d)(X,d) be a compact metric space and let f:X→Rf:X\to\mathbb{R}f:X→R be continuous . Then fff is bounded : there exists M<∞M<\inftyM<∞ such that ∣f(x)∣≤M|f(x)|\le M∣f(x)∣≤M for all x∈Xx\in Xx∈X. Connection to parent theorem: By the extreme value theorem , fff attains a maximum M+M_+M+​ and a minimum M−M_-M−​. Then ∣f(x)∣≤max⁡{∣M+∣,∣M−∣}|f(x)|\le \max\{|M_+|,|M_-|\}∣f(x)∣≤max{∣M+​∣,∣M−​∣}. ...

1 min

Continuous function on a compact set is uniformly continuous

Corollary (Heine–Cantor): Let (X,dX)(X,d_X)(X,dX​) be a compact metric space and let (Y,dY)(Y,d_Y)(Y,dY​) be a metric space. If f:X→Yf:X\to Yf:X→Y is continuous , then fff is uniformly continuous on XXX. Connection to parent theorem: This is precisely the Heine–Cantor theorem .

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Continuous functions are Riemann integrable

Continuous functions are Riemann integrable: If f:[a,b]→Rf:[a,b]\to\mathbb{R}f:[a,b]→R is continuous , then fff is Riemann integrable on [a,b][a,b][a,b]. This theorem guarantees that the Riemann integral covers all standard functions from calculus and is a basic entry point for more refined integrability criteria. Proof sketch: A continuous function on the compact interval [a,b][a,b][a,b] is uniformly continuous . Given ε>0\varepsilon>0ε>0, choose δ>0\delta>0δ>0 so that ∣x−y∣<δ|x-y|<\delta∣x−y∣<δ implies ∣f(x)−f(y)∣<ε/(b−a)|f(x)-f(y)|<\varepsilon/(b-a)∣f(x)−f(y)∣<ε/(b−a). Take a partition PPP with mesh <δ<\delta<δ. Then on each subinterval, the oscillation of fff is <ε/(b−a)<\varepsilon/(b-a)<ε/(b−a), so U(f,P)−L(f,P)<εU(f,P)-L(f,P)<\varepsilonU(f,P)−L(f,P)<ε, proving integrability. ...

1 min

Continuous functions have the intermediate value property

Corollary (Intermediate Value Theorem): Let I⊆RI\subseteq\mathbb{R}I⊆R be an interval and let f:I→Rf:I\to\mathbb{R}f:I→R be continuous . If a,b∈Ia,b\in Ia,b∈I and yyy lies between f(a)f(a)f(a) and f(b)f(b)f(b), then there exists ccc between aaa and bbb such that f(c)=y. f(c)=y. f(c)=y. Connection to parent theorem: This is the intermediate value theorem , which follows from connectedness of intervals and the fact that continuous images of connected sets are connected subsets of R\mathbb{R}R, hence intervals. ...

1 min

Continuous functions map compact sets to closed and bounded sets in R^k

Let (X,d)(X,d)(X,d) be a metric space , let K⊆XK\subseteq XK⊆X be compact , and let f:K→Rkf:K\to\mathbb{R}^kf:K→Rk be continuous . Proposition: The image f(K)⊆Rkf(K)\subseteq\mathbb{R}^kf(K)⊆Rk is closed and bounded . This is the Euclidean specialization of “continuous image of compact is compact ” plus the Heine–Borel characterization of compact sets in Rk\mathbb{R}^kRk. ...

1 min

Continuous functions on compact sets are bounded

Let (X,d)(X,d)(X,d) be a metric space , let K⊆XK\subseteq XK⊆X be compact , and let f:K→Rf:K\to\mathbb{R}f:K→R be continuous . Proposition: The function fff is bounded on KKK: there exists M<∞M<\inftyM<∞ such that ∣f(x)∣≤M|f(x)|\le M∣f(x)∣≤M for all x∈Kx\in Kx∈K. This proposition is one of the core reasons compactness is the right hypothesis for global control from local continuity. ...

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Continuous image of compact set is compact

Continuous image of compact set is compact: Let (X,dX)(X,d_X)(X,dX​) and (Y,dY)(Y,d_Y)(Y,dY​) be metric spaces , let K⊆XK\subseteq XK⊆X be compact , and let f:X→Yf:X\to Yf:X→Y be continuous . Then f(K)⊆Yf(K)\subseteq Yf(K)⊆Y is compact. This is one of the most important permanence properties of compactness and is used to prove the extreme value theorem and many existence statements. ...

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Continuous image of connected set is connected

Continuous image of connected set is connected: Let (X,dX)(X,d_X)(X,dX​) and (Y,dY)(Y,d_Y)(Y,dY​) be metric spaces , let E⊆XE\subseteq XE⊆X be connected , and let f:X→Yf:X\to Yf:X→Y be continuous . Then f(E)⊆Yf(E)\subseteq Yf(E)⊆Y is connected. This theorem is a basic structural fact: continuous maps cannot “tear apart” connected sets. It implies, for example, that continuous real functions map intervals to intervals. ...

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Contraction mapping

Let (X,d)(X,d)(X,d) be a metric space and let T:X→XT:X\to XT:X→X. The map TTT is a contraction mapping (or contraction) if there exists a constant c∈[0,1)c\in[0,1)c∈[0,1) such that for all x,y∈Xx,y\in Xx,y∈X, d(T(x),T(y))≤c d(x,y). d\bigl(T(x),T(y)\bigr)\le c\,d(x,y). d(T(x),T(y))≤cd(x,y). The constant ccc is called a contraction constant. A contraction is a special case of a Lipschitz map: TTT is Lipschitz with constant LLL if d(Tx,Ty)≤Ld(x,y)d(Tx,Ty)\le L d(x,y)d(Tx,Ty)≤Ld(x,y) for all x,yx,yx,y. Contractions are exactly Lipschitz maps with L<1L<1L<1. ...

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