Convergent sequences are Cauchy

Convergence implies the Cauchy property in any metric space
Convergent sequences are Cauchy

Proposition. If (xn)(x_n) is a convergent sequence in a metric space, then it is a .

Proof sketch. If xnax_n\to a, then for ε>0\varepsilon>0 choose NN such that d(xn,a)<ε/2d(x_n,a)<\varepsilon/2 for all nNn\ge N. For m,nNm,n\ge N,

d(xm,xn)d(xm,a)+d(a,xn)<ε/2+ε/2=ε d(x_m,x_n)\le d(x_m,a)+d(a,x_n)<\varepsilon/2+\varepsilon/2=\varepsilon

by the triangle inequality.