Bounded Linear Functional and Its Norm

A linear functional is bounded iff it is continuous; its operator norm is sup_{||x||≤1}|f(x)|.
Bounded Linear Functional and Its Norm

Let XX be a over R\mathbb{R} or C\mathbb{C}. A f:XKf:X\to\mathbb{K} (where K{R,C}\mathbb{K}\in\{\mathbb{R},\mathbb{C}\}) is a linear functional.

The functional ff is bounded if there exists M>0M>0 such that

f(x)Mxfor all xX. |f(x)|\le M\|x\|\quad\text{for all }x\in X.

In normed spaces, boundedness is equivalent to continuity.

The norm (operator norm) of ff is

f:=supx1f(x). \|f\|:=\sup_{\|x\|\le 1}|f(x)|.

Equivalently, f=inf{M>0:f(x)Mx x}\|f\|=\inf\{M>0: |f(x)|\le M\|x\|\ \forall x\}.

This notion is used in and in separation results such as .

Examples:

  • On X=RnX=\mathbb{R}^n with the Euclidean norm, f(x)=a,xf(x)=\langle a,x\rangle is bounded and f=a2\|f\|=\|a\|_2.
  • If X=C[0,1]X=C[0,1] with \|\cdot\|_\infty, then f(x)=x(t0)f(x)=x(t_0) is bounded with f=1\|f\|=1.