Uniform continuity implies continuity

Uniform continuity gives a single delta that works at every point, hence pointwise continuity
Uniform continuity implies continuity

Let (X,dX)(X,d_X) and (Y,dY)(Y,d_Y) be and let f:XYf:X\to Y.

Proposition: If ff is on XX, then ff is at every point of XX.

Uniform continuity is strictly stronger than continuity in general, but on sets they coincide ( ).

Proof sketch: Fix x0Xx_0\in X and ε>0\varepsilon>0. Uniform continuity gives δ>0\delta>0 such that dX(x,y)<δd_X(x,y)<\delta implies dY(f(x),f(y))<εd_Y(f(x),f(y))<\varepsilon for all x,yXx,y\in X. Apply this with y=x0y=x_0 to get continuity at x0x_0.