Fubini's Theorem (Riemann, continuous case)

A continuous function on a rectangle can be integrated by iterated one-dimensional integrals
Fubini's Theorem (Riemann, continuous case)

Fubini’s Theorem (Riemann, continuous case): Let f:[a,b]×[c,d]Rf:[a,b]\times[c,d]\to\mathbb{R} be . Define g(x)=cdf(x,y)dy(x[a,b]),h(y)=abf(x,y)dx(y[c,d]). g(x)=\int_c^d f(x,y)\,dy \quad (x\in[a,b]), \qquad h(y)=\int_a^b f(x,y)\,dx \quad (y\in[c,d]). Then gg and hh are continuous, and the exists and satisfies $ \int_a^b\left(\int_c^d f(x,y),dy\right)dx

\int_{[a,b]\times[c,d]} f(x,y),d(x,y)

\int_c^d\left(\int_a^b f(x,y),dx\right)dy. $

This theorem justifies computing multiple integrals by integrating one variable at a time via , a core technique in analysis and applications.

Proof sketch: Continuity on the rectangle implies and boundedness. Approximate ff uniformly by on rectangles (or compare / ). For step functions the statement is immediate by finite additivity. Uniform approximation plus the yields the equality for ff.