Continuous functions map compact sets to closed and bounded sets in R^k

If K is compact and f is continuous into R^k, then f(K) is closed and bounded
Continuous functions map compact sets to closed and bounded sets in R^k

Let (X,d)(X,d) be a , let KXK\subseteq X be , and let f:KRkf:K\to\mathbb{R}^k be .

Proposition: The f(K)Rkf(K)\subseteq\mathbb{R}^k is and .

This is the Euclidean specialization of “ ” plus the characterization of compact sets in Rk\mathbb{R}^k.

Proof sketch: Since ff is continuous and KK is compact, f(K)f(K) is compact in Rk\mathbb{R}^k. By Heine–Borel, compact subsets of Rk\mathbb{R}^k are closed and bounded. Therefore f(K)f(K) is closed and bounded.