Image is a subring

The image of a ring homomorphism is closed under the ring operations.
Image is a subring

Image is a subring: Let φ:RS\varphi:R\to S be a ring homomorphism. Then

im(φ)={φ(r):rR} \operatorname{im}(\varphi)=\{\varphi(r):r\in R\}

is a subring of SS. If φ\varphi is unital, then im(φ)\operatorname{im}(\varphi) contains 1S1_S.

Thus the of a naturally inherits the structure of a of the codomain, and in the setting it is a unital subring. Combined with , this yields identifying R/kerφR/\ker\varphi with imφ\operatorname{im}\varphi.