Third isomorphism theorem for modules
If A ⊆ B ⊆ M then (M/A)/(B/A) ≅ M/B.
Third isomorphism theorem for modules
Third isomorphism theorem (modules): Let be an -module and let be submodules . Then there is a natural isomorphism
of -modules, where each quotient is a quotient module .
This theorem expresses the compatibility of iterated quotients and is fundamental in organizing “modding out step by step” in module theory.
Proof sketch (optional): Use the natural surjection induced from ; its kernel is . Apply the first isomorphism theorem to that map.