First isomorphism theorem for modules

A module homomorphism induces an isomorphism M/ker f ≅ im f.
First isomorphism theorem for modules

First isomorphism theorem (modules): Let f ⁣:MNf\colon M\to N be a . Then the induced map

f ⁣:M/ker(f)im(f),f(m+ker(f))=f(m), \overline f\colon M/\ker(f)\longrightarrow \mathrm{im}(f),\qquad \overline f(m+\ker(f))=f(m),

is an isomorphism of RR-modules. Here ker(f)\ker(f) is the and im(f)\mathrm{im}(f) is the , and M/ker(f)M/\ker(f) is a .

This theorem identifies the “effective domain” of a map with its image and is the basic mechanism behind many results in the theory of ; it is the module analogue of

Proof sketch: Define f\overline f as above; it is well-defined because elements differing by ker(f)\ker(f) have the same image. Surjectivity is immediate from the definition of im(f)\mathrm{im}(f), and injectivity follows because f(m+ker(f))=0\overline f(m+\ker(f))=0 implies mker(f)m\in\ker(f). Linearity is inherited from ff.