Third Isomorphism Theorem (Groups)

If N ⊆ K ⊲ G with N ⊲ G, then (G/N)/(K/N) ≅ G/K
Third Isomorphism Theorem (Groups)

Third Isomorphism Theorem (Groups). Let GG be a and let NGN \trianglelefteq G and KGK \trianglelefteq G be with NKN \subseteq K. Then K/NK/N is a normal subgroup of G/NG/N, and there is a canonical isomorphism of

(G/N)/(K/N)G/K, (G/N)/(K/N) \cong G/K,

induced by the map gNgKgN \mapsto gK.

This theorem formalizes the idea that “quotienting by NN and then by K/NK/N” is the same as quotienting directly by KK. It can be viewed as a special case of , or proved directly using .

Proof sketch. Define a homomorphism G/NG/KG/N \to G/K by gNgKgN \mapsto gK; it is surjective. Its kernel is precisely K/NK/N. Apply the first isomorphism theorem to conclude (G/N)/(K/N)G/K(G/N)/(K/N) \cong G/K.