Schreier's Lemma

A subgroup of a finitely generated group is generated by Schreier generators from a transversal
Schreier's Lemma

Schreier’s Lemma: Let GG be a generated by a set SS (i.e. every element of GG is a finite product of elements of SS1S\cup S^{-1}). Let HGH\le G be a . Choose a right transversal TGT\subseteq G for HH in GG, meaning: for every right HgHg there exists a unique tTt\in T with Hg=HtHg=Ht.

For tTt\in T and sSs\in S, let tsT\overline{ts}\in T be the unique representative with Hts=HtsHts=H\overline{ts}. Then HH is generated by the Schreier generators ts(ts)1H(tT, sS). t\,s\,(\overline{ts})^{-1}\in H \qquad (t\in T,\ s\in S).

This is a core tool for proving results about generators of subgroups, including the .

Proof sketch: Any hHh\in H is a word in SS1S\cup S^{-1}. Track the successive coset representatives in TT as you read the word; inserting and removing these representatives rewrites hh as a product of elements of the form ts(ts)1t s (\overline{ts})^{-1}, showing these elements generate HH.