Kernels are Normal Subgroups

The kernel of a group homomorphism is invariant under conjugation
Kernels are Normal Subgroups

Kernels are Normal Subgroups: Let f:GHf:G\to H be a between groups. Then the ker(f)\ker(f) is a of GG.

This fact is what makes naturally arise from homomorphisms, and it underlies the .

Proof sketch: First, ker(f)\ker(f) is a by a subgroup test. For normality, if kker(f)k\in\ker(f) and gGg\in G, then f(gkg1)=f(g)f(k)f(g)1=f(g)ef(g)1=ef(gkg^{-1})=f(g)f(k)f(g)^{-1}=f(g)e f(g)^{-1}=e, so gkg1ker(f)gkg^{-1}\in\ker(f); apply the normality criterion.