Theorem (FTGT).
Let L/K be a finite Galois extension
with Galois group
G=Gal(L/K). There is an inclusion-reversing bijection
{intermediate fields K⊆E⊆L}⟷{subgroups H≤G},given by
E↦Gal(L/E),H↦LH:={x∈L:σ(x)=x ∀σ∈H},the fixed field
of H.
It satisfies:
- [L:E]=∣Gal(L/E)∣ and [E:K]=[G:Gal(L/E)] (compare degree = group order
).
- E/K is Galois iff Gal(L/E)⊴G, and then Gal(E/K)≅G/Gal(L/E).
Examples.
- L=Q(2), G≅C2: subgroups are {1} and G, corresponding to fields L and Q.
- L=Fpn over K=Fp: G is cyclic of order n (see finite-field Galois groups
); subgroups correspond to subfields Fpd with d∣n.
- For the splitting field of x3−2 over Q, G≅S3; intermediate fields correspond to subgroups of S3.
Related. Galois correspondence (core bijection)
, Artin's theorem on fixed fields
.