Frobenius endomorphism

In characteristic p>0, the map Fr(x)=x^p is a ring homomorphism; on finite fields it is an automorphism.
Frobenius endomorphism

Definition. Let KK be a field of characteristic p>0p>0. The Frobenius endomorphism is the map

Fr:KK,Fr(x)=xp. \mathrm{Fr}:K\to K,\qquad \mathrm{Fr}(x)=x^p.

It is a ring homomorphism because (x+y)p=xp+yp(x+y)^p=x^p+y^p in characteristic pp. For fields it is always injective; it is surjective exactly when KK is .

On a finite field Fpn\mathbb{F}_{p^n}, Frobenius is an automorphism and generates the of Fpn/Fp\mathbb{F}_{p^n}/\mathbb{F}_p.

See also. , .

Examples.

  1. On Fp\mathbb{F}_p, Frobenius is the identity map since xp=xx^p=x for all xFpx\in\mathbb{F}_p.
  2. On Fpn\mathbb{F}_{p^n}, the automorphisms fixing Fp\mathbb{F}_p are Frk:xxpk\mathrm{Fr}^k:x\mapsto x^{p^k} for k=0,,n1k=0,\dots,n-1.
  3. On K=Fp(t)K=\mathbb{F}_p(t), Frobenius is not surjective: there is no element uKu\in K with up=tu^p=t.