Existence of Algebraic Closures

Every field has an algebraic closure.
Existence of Algebraic Closures

Theorem (Existence).
For every field KK, there exists an extension field K\overline{K} such that:

  1. K/K\overline{K}/K is an , and
  2. K\overline{K} is .

Such a field K\overline{K} is called an algebraic closure of KK. Standard proofs use (hence ).

Examples.

  1. An algebraic closure of R\mathbb{R} is C\mathbb{C} (every complex number satisfies a quadratic over R\mathbb{R}).
  2. An algebraic closure of Fp\mathbb{F}_p is the union n1Fpn\bigcup_{n\ge1}\mathbb{F}_{p^n} inside a fixed ambient algebraic closure.
  3. Q\overline{\mathbb{Q}} denotes an algebraic closure of Q\mathbb{Q} (often viewed inside C\mathbb{C}).

Related. .