Maximal ideal of a local ring

In a local ring (R,m), there is a unique maximal ideal m, and the units are exactly R \ m.
Maximal ideal of a local ring

Let RR be a . Its defining feature is that it has a unique , usually denoted m\mathfrak m.

Statement

If (R,m)(R,\mathfrak m) is a local ring, then:

  1. m\mathfrak m is the unique maximal ideal of RR.
  2. An element uRu\in R is a iff umu\notin \mathfrak m. Equivalently, R×=Rm. R^\times = R\setminus \mathfrak m.
  3. The of RR equals m\mathfrak m: J(R)=m. J(R)=\mathfrak m.
  4. Via the k=R/mk=R/\mathfrak m, an element uRu\in R is a unit iff its image in kk is nonzero.

Examples

  1. Z(p)\mathbb Z_{(p)}.
    In the Z(p)\mathbb Z_{(p)}, the maximal ideal is pZ(p)p\mathbb Z_{(p)}. The units are fractions a/ba/b with pap\nmid a.

  2. k[[x]]k[[x]].
    In , the maximal ideal is (x)(x). A power series is a unit iff its constant term is nonzero.

  3. k[x,y](x,y)k[x,y]_{(x,y)}.
    The localization of k[x,y]k[x,y] at the maximal ideal (x,y)(x,y) is local with maximal ideal generated by xx and yy.